started car fleet problem with enumerate method

NeetCodeRoadmap/Stack/739_Daily_Temperatures.py

@@ -47,6 +47,7 @@ class Solution(object):
         for i, t in enumerate(temperatures): #looping through temperatures array and their index
             while stack and t > stack[-1][0]: # is our stack empty and is our temperature greater than the top of our stack
                 stackT, stackInd = stack.pop()
+                print(f'i {i}: t {t}')
                 res[stackInd] = (i - stackInd) # compute the days it took us to find a higher temperature
             stack.append((t,i)) # append to the stack the temperature and index
         return res

NeetCodeRoadmap/Stack/853_Car_Fleet.py

@@ -0,0 +1,30 @@
+class Solution(object):
+    def carFleet(self, target, position, speed):
+        """
+        There are n cars going to the same destination along a one-lane road. The destination is target miles away.
+
+        You are given two integer array position and speed, both of length n, where position[i] is the position of 
+        the ith car and speed[i] is the speed of the ith car (in miles per hour).
+
+        A car can never pass another car ahead of it, but it can catch up to it and drive bumper to bumper at the 
+        same speed. The faster car will slow down to match the slower car's speed. The distance between these two 
+        cars is ignored (i.e., they are assumed to have the same position).
+
+        A car fleet is some non-empty set of cars driving at the same position and same speed. Note that a 
+        single car is also a car fleet.
+
+        If a car catches up to a car fleet right at the destination point, it will still be considered as one car fleet.
+
+        Return the number of car fleets that will arrive at the destination.
+        :type target: int
+        :type position: List[int]
+        :type speed: List[int]
+        :rtype: int
+        """
+        fleets = []
+        for i,p in enumerate(position):
+            print(f'{i}: {p}')
+
+        
+obj = Solution()
+print(obj.carFleet(12,[10,8,0,5,3],[2,4,1,1,3])) # 3