passed all test cases using comparison of dictionaries
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@ -4,4 +4,24 @@ def isAnagram(s, t):
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:type t: str
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:rtype: bool
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"""
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seen = {}
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check = {}
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count = 0
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for letter in s:
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if letter in seen:
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seen[letter] += 1
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else:
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seen[letter] = 1
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for letter in t:
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if letter in check:
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check[letter] += 1
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else:
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check[letter] = 1
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if seen != check:
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return False
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else:
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return True
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print(isAnagram("anagram", "nagaram"))
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print(isAnagram("rat", "car"))
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print(isAnagram("a", "ab"))
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